International Journal of Scientific & Engineering Research Volume 2, Issue 10, Oct-2011 1
ISSN 2229-5518
Decomposition of
Cr [ Km ]
into
sunlet graphs
A. D. Akinola
Cr [K m ]
(which is the wreath product of cycle and complem ent of
n | rm2
a complet e graph n
can be decompose into sunlet graph n , n = rm if and only if
and m is even.
2000 Mathem atics subject classification: 05B30, 05C70
—————————— ——————————
Cycles
Crm . R.Anitha etal [7] worked on
We begin with a few definitions.A graph
Cr [ Km ] is a graph which arises from the
N-sun (sunlet graph) decomposition
of complete ,complete Bipartite and some
cycle Cr
by replacing each vertex x by m
harary graphs . Little attention has
independent vertices and each edge xy by
x' y' , x' y' ',..., x' ym1 ; x' ' y' ,..., x' ' ym
.
been paid to the same problem for the
graph Cr [K m ] . A significant and useful result is that of Sotteau [8] who discover
,..., x m y' ,..., x m ym
A graph G with q edges is said to be decomposable into graph H if it can
be written as the union of edge-disjoint copies of H so that every edge in G belongs to one and only one copy of H . Although much work has gone into decomposition of complete graphs into
k cycles(See [4] for good survey).Alspach
and Gavlas [1] have shown the necessary and sufficient condition for Cm to decompose the complete graph Kn
when m and n are either both odd and
even.M. Sajna [2] have shown that for the case when m and n are of opposite parity.N.J. Cavenagh and etal [3] have worked on decomposition of complete
multipartite graphs into cycles of even
necessary and sufficient conditions for the decomposition of complete bipartite graphs into k cycles.
Sunlet graph Lr is a graph with cycle Cr
2
whereby each vertex of the cycle is attached to one pendant vertex .Each sunlet graph contains r vertices with r edges.
We will define a function on the vertices of a graph G = Cr [K m ] as
length.D. Froncek etal worked on
c : V (G) xN N
i.e for every vertex
decomposition of complete graph into blownup cycles Cr [ [K2 ] . R. Haggkvist [5] gave lemma on cycle decomposition. N.J.
Cavenagh [10] have shown that the graph
x G , c( x) xij where i, j N .
All graphs in this paper are simple .We
Cr [ Km ]
can be decompose into cycle
use Km
to denote the complete graph
Cr . R. Laskar [11] has proved that the
on m vertices. Km
denote the
graph Cr [ Km ]
can be decompose into
complement of K m . An r-cycle is a cycle
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International Journal of Scientific & Engineering Research Volume 2, Issue 10, Oct-2011 2
ISSN 2229-5518
of length r and is denoted by Cr . Let
( x'i )
and ( x''i )
represent pendant
Cr [ Km ]
stand for a cycle in which every
vertices.Attached each pendant vertices
vertex is replaced by m isolated vertices
( x'i )
to each vertex x'i
in C 'r
and
and every edge by Km, m
and Cr [K m ]
( x' 'i )
to each vertex x''i in C ''r
, C ''r
contains vertex xij
; i = 1,…, r and j =
with pendant vertices ( x'i ) , ( x' 'i )
attached respectively gives 2 sunlet graphs
0,…,m-1. Let Ln
be a sunlet graph with n
vertices and n edges.
with 2r vertices.Hence Cr [K 2 ]
can be
Let G be a graph without loops and
decompose into 2 sunlet graphs with 2r
vertices
.
L (H1 , H 2 ,..., H m )
a list of graphs.The
Let r,m be positive even integers such that
list L is proper if G has a subgraph
isomorphic with H i , i = 1, 2,…,m
n = rm then Cr [ Km ]
can be decompose
m
and |E (G)|= | E (H i ) |
i 1
where E(G)
into m sunlet graph Lr .
Proof:
denotes the edge set of G .The
list L is said to pack G if G is the edge-
First observe that Cr [ K 2 ]
can be
disjoint union of the graphs
decompose into 2 sunlet graphs with 2r
vertices.Then set m = 2t and decompose
G1 , G2 ,...,Gm (G G1 G2 ... Gm )
C [K ]
into t 2 cycles C .Denote vertices
where Gi is isomorphic with H i
for
r t r
i = 1,2,…,m .An even list where each entry
in i - th part of Cr [Kt ]
by xij
for j = 0,
occurs an even number of times. The
,…,t- 1 and create t cycles
graph G is said to have an M-
xij x2 j x3 j ...xr 1 j xrj
for j = 0,1,…, t-1. Next
decomposition if the proper list
(M,M,…,M) packs G,that is M|G.
combine these cycles into one cycle Crt
by replacing each edge x1 j x2 j
with
3. DECOMPOSITION OF Cr [ Km ]
x1 j x2 j 1 .Now apply mappings s
0, 1,…, t- 1 defined as follows:
for s =
s ( xij ) xij
s ( xij ) xij s
for i odd and
for i even. This is the
The graph Cr [K 2 ]
can be decompose
desired decomposition into cycles
into 2 sunlet graphs with 2r vertices.
Proof.
Crt .Now take each cycle
Crt ,make it back into Crt [ K 2 ]
and
From the definition of the graph Cr [ K2 ]
(denoted by Cr [2] ), each vertex x
decompose Crt [K 2 ]
into 2 sunlet graphs
L2 rt Lrm Ln .Hence Ln
decomposes
in Cr
is replaced by a pair of two
Cr [K m ]
for r,m even and n = rm.
independent vertices x', x' '
and each
Each graph Crt [ K 2 ]
gives 2 sunlet
edge xy is replaced by four edges
x' y', x' y' ', x' ' y', x'' y'' First form 2
graphs Ln and we have t graph Crt [K 2 ]
cycles C'r
and C' 'r
with vertex set x'i
which implies that we have 2t = m sunlet
graphs Ln .Hence Cr [K m ] decomposes
and x' 'i ] respectively, i = 1,…, r. Define a
into m sunlet graphs Ln .
mapping Á by ( x'i ) x''i 1
and
( x''i ) x'i 1 , i is calculated modulo r.
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If r is a positive odd integers and m a positive even integers such that n =
rm,then sunlet graph Ln .decomposes
follows:
s ( xij ) xij
for i odd and
s ( xij ) xi j s
for i even and i = r.m
Cr [ Km ] .
Proof:
We have r- 1 even since r is odd.Set m = 2t.
Now take each Crt ,make it into Crt [ K 2 ]
and decompose it into two sunlet
First create k cycles Cr 1 in Cr 1[K m ] as
Graphs L2 rt
= Lrm Ln Hence sunlet
in lemma (2).Then take complete tripartite
graph Ln
decompose Cr [K m ]
for r odd.
graph Kt ,t ,t
with partite sets X i {xij}
Therefore for m 2 , r
odd, Cr [ Km ]
can
for i = 1, r – 1, r and j = 0, 1,…, t- 1 and
decompose it into triangles using well
known construction via latin square.i.e
be decomposes into m sunlet graph Ln .
Construct t t
latin square and consider
each element in the form (a ,b, c) where a
If sunlet graph Ln
decomposes Cr [ Km ] ,
denotes the row,b denotes the column and
c denotes the entry with
0 a, b, c t 1 .Each cycle is of the
n = rm, then m is even.
Proof:
Each vertex in Cr [Km ]
has degree 2m.
form (1, a) , (r- 1, b) , (r, c)
For L to decompose C [K ]
with
n r m
Then for every triangle x1a xr 1b xrc
n = rm,3w+p must be equal to 2m where w,
replace the edge x1a xr 1b
in an
p represent the number of times
appropriate Cr 1
by the edges xr 1b xrc
the vertex xij
in Cr [K m ]
appears in the
and xrc x1a
to obtain cycle Cr :
decomposition with degree 3 and 1 respectively and w + p = m .Suppose m is
Therefore we have Cr | Cr [Kt ] .
m
odd,let there exist a vertex xij
in Cr [Km ]
Case 1 :Suppose
2
is even.
such that it exist in each sunlet graph Ln
Join 2 cycles Cr
into one cycle to give
that decomposes Cr [K m ] .The sum of its
C2 r : i.e
degree in all the sunlet graphs Ln
is 3w+p.
xij x2 j x3 j ...xr 1 j xrj xij1x2 j 1...xrj 2 ,
In all the cases for the values of w and p,
j 0,1,...,t 2
3w+p 6= 2m.which implies that Ln
does
Now apply mapping s
for s = 0, 1,…,
not decomposes Cr [K m ]
for m odd but
t- 1 defined as follows:
for all m even,3w + p = 2m.The result also
s ( xij ) xij
for i odd and s ( xij ) xij s
follows from [8] for r > 2.Hence the result.
for i even and i = r.
This is the desired decomposition into
cycles C2 r .Now take each C2 r , make
If G = Cr [ Km ]
can be decompose into
it into C2r [K2 ] . and decompose it into
cycle Cr
then G(2) can be decompose
two sunlet graphs L4 r . .
m
into 2m2 sunlet graphs with 2r vertices.
Proof:
Case 2: Suppose
, is odd
From the previous observation all we need
2 to show is that Cr [2]
decomposes
Join the cycles Cr by replacing each edge
into 2 copies of sunlet graphs with 2r
x1 j x2 j with x1 j x2 j 1 . in order to
vertices.By Lemma (3.1) , Cr [K2 ]
can
create t cycles Crt .Then apply mapping
be decompose into 2 sunlet graphs with 2r
2
s for s = 0, 1,…t - 1 defined as
vertices.Hence we have 2m sunlet
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International Journal of Scientific & Engineering Research Volume 2, Issue 10, Oct-2011 4
ISSN 2229-5518
graph L2r
since we have m cycles Cr
r m
< 2r with
from the cycle decomposition of Cr [ Km ]
m(m 2) 0(mod r)
r [ m ]
,then C K
can
be decomposed into sunlet graph Ln of
3.6 Lemma
length n for all m r
with
Necessary conditions for Ln to
m(m 2) 0(mod r) .
decompose Cr [ Km ]
whenever n = rm are:
Proof:
(a) m must be positive even integers.
Suppose that Cr [K m ]
can be
(b) r 3
(c) The number of edges n divides the
decomposed into sunlet graphs Ln
whenever m(m 2) 0(mod r) and
number of edges in Cr [ Km ] .
r m
< 2r.Let m and r be positive even
Proof:
(a) The result follows from lemma (3.4)
that m must be positive integers.
integers such that
m(m 2) 0(mod r) .Let m = pr + t for
integers p with 0 < t < r .Observe that
(b) It follows from lemma (3.2) and (3.3).
m(m 2) 0(mod r)
implies that m or
(c) It follows from the fact that the number
m 2 is a multiple of r. If m = pr+t then t
of edges n of Ln
has to be a
is either 0 or 2 .Since r is even, then
multiple of m since the total number of
2
r(r 2) 0(modt ) as well .Partition the
edges in Cr [Km ]
is rm .Thus for such
edge set of Cr [K m ]
into m sets such that
decomposition to exist, we have that n|rm.
each set induces a subgraph isomorphic to
mr
3.7 Theorem
Let m, n be positive even integers and
sunlet graph Ln
in such a way that
t
mr
r 3 , n = rm,if Ln
decomposes Cr [ Km ]
vertices will have degree 3 and
t
then the 2 sunlet graphs such that each
vertex appears once with degree 3 and
vertices have degree 1.If there exist a vertex xij such that the degree of the
1 in each sunlet graph Ln
respectively is a
4 regular graph which can be decompose
vertex xij
is either 3 or 1.i.e for Ln to
into 2 hamiltonian cycles.
Proof:
Suppose the sunlet graph Ln
decomposes
decompose
n
Cr [K m ] , deg(xij ) 2m, xij V ( Ln )
i 1
which follows from lemma (3.2).We
Cr [ Km ] ,let m = 2t.Then by lemma (3.1)
now use induction on p.It is true from
and lemma (3.2) and [8]; Crt| Cr [Kt ] .Let
lemma (3.2) that Ln
decomposes Cr [ Km ]
G = Cr [Kt ] . then by theorem (3.4) G(2)
can be decompose into sunlet graphs with
for p = 1.Suppose p > 1,assume that it is
true for p = k.Suppose p = k+1,then
m = (k + 1) r + t.
2rt = rm vertices.The
join of these 2 sunlet graphs gives 4
regular graphs which can be decompose
, deg(xij )
3((k 1)r t )
2
(k 1)r t
2 ,
into 2 hamilton cycles which follows from the result of Bermond etal [9].
3.8 Theorem
Let r, m, n be positive even integers satisfying 3 < r · m. If Cr [ Km ] , can be decomposed into sunlet graph Ln of
length n = rm for all m in the range
i 1 2((k 1)r t ) 2m
It is true for p = k+ 1,therefore it is true for all integer p. Therefore Ln
decomposes Cr [Km ]
for all m > r.Hence the result.
4 Main result
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4.1 Theorem
2
Let Cr [Km ] G
with rm2
Let G = Cr [K m ]
with rm
edges, r ,m even .Let H be a collection of m
edges r, m even, n = rm ,let H be a collection of m disjoint sunlet graphs on 2n vertices .Then G(2) L'2n L' '2n
where L'2 n L''2n H .
disjoint sunlet graphs Ln , n = rm. Then
G(2) G1 G 2 G 3 G 4
where
G1 G 2 G 3 G 4 H .
Therefore
Proof:
H | G(2) .
Therefore H | G (2)
.
First show that G(2) L'2n L' '2n . From
Proof:
Assume that H consists of disjoint sunlet
lemma (3.2), Ln
decomposes Cr [ Km ]
into m sunlet graph with n vertices.i.e
m
graphs Ln with lengths n1 , n2 ,..., nnm
k 1
Lni decomposes Cr [Km ] G .Next
Where m rm2 nm . Let G consist of
show that Ln 2 k decomposes G(2).It is
sufficient to show that Lnk (2)
k 1
set of vertices xij , i 1,..., r
can be decompose into 2 copies of Ln 2 k
And
j 0,1,..., m 1
with rm 2
edges and G(2) be a graph with
, k = 1,...,m. First form 2 cycles C'nk
4rm 2
edges and 2rm
vertices.Let
and C ' 'nk
with vertex set x'ij
G1 , G 2 , G 3 , G 4
be the subgraph of G(2)
and x' 'ij .Define a mapping f by
with equal number of vertices and edges
f ( x'ij ) y'ij and
f ( x' 'ij ) y' 'ij
i.e
G1 contains the set of vertices {x' }
where
y'ij , y' 'ij represent the pendant ij
vertices of Lnk (2) .Attached each pendant
with edge set {x'ij x'i 1 j } .
G 2 contains the set of vertices {x' ' }
vertices
f ( x'ij ), f ( x' 'ij ) to each vertex ij
x'ij , x' 'ij
in C'nk , C' 'nk
respectively.
with edge set {x' 'ij x''i 1 j }.
3
C 'nk , C ' 'nk
with pendant vertices
G contains the set of vertices
f ( x'ij ), f ( x' 'ij )
{x'ij , x' 'i 1 j } with edge set {x'ij x''i 1 j } 2
attached respectively gives 2 sunlet graphs L'2 nk , L''2nk . Therefore Lnk (2) can be decompose into 2 sunlet graph L'2 nk , L''2nk .i.e
Lnk (2) L'2 nk L' '2nk .Therefore
m
G 4 contains the set of
vertices {x' 'ij , x'i 1 j } with edge set
{x' 'ij x'i 1 j }
Since each G a , a 1,2,3,4
consists of rm edges then G a
partition G(2) that is
G(2) Lnk (2)
k 1 .
G(2) G1
G 2
G 3
G 4 .
m m Each G a
has sunlet graph decomposition
L'2nk L''2 nk L'2 n L' '2n
which follows from lemma (3.2).Then
k 1
Where
k 1
m
a a
G L nk m
k 1
L2 n L2nk .Hence H | G(2) since
k 1
L'2n L' '2 n H .
4.2. Theorem
Therefore G a H
Hence
H | G (2) .
4.3 Corollary
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ISSN 2229-5518
Let Cr [Km ] G
be a graph with sunlet
graphs L1n ,..., Ll n , from L [ K ] , as
graph decomposition (that is a decomposition into edge-disjoint sunlet graphs).Then any proper even list of sunlet graphs Ln , n = rm packs G(2). Proof:
n l
follows:
Form the cycle Cn from l l , latin
2
square as
(1, u)(2, v)(3, u)...( m 1, v)( n , ) ,
A sunlet graph in G(2) is a cycle together 2 2
with pendant vertices attached
to each vertex of the cycle.Assume that
where u is the row ,v is the column and
is the entry in the latin square. Next
join each vertex of the cycle to pendant
(Ln1 , Ln1, Ln1 , Ln1, Ln 2 , Ln 2 , Ln 2 , Ln 2 , Lnm , Lnm , Lnvme,rLtincme,s)
xij
for l
in order to get
is a proper even list of sunlet graphs on n
vertices.Where n is the order of G.
sunlet graph Ln .Therefore
L [K ] L 1 ... Ll n .Hence sunlet
n l n
Ln1 Ln 2 ... Lnm be a sunlet graph
graph L decomposes C [K
] for any
decomposition of G.
Let Lnk Ln , k 1,..., m .By theorem
(4.2),
m
n
positive integer l .
4.5 Corollary
r ml
L (2)
La nk , a 1,2,3,4 i.e
Let G Cr [ K m ]
be a graph with sunlet
nk
k 1
graph decomposition then any even
Lnk (2) L nk L nk L nk L nk
list of sunlet graph Ln
packs G(l ) for
1 2 3 4
where L1nk L2 nk L3nk L4 nk Whence
G(2) Ln1 (2) L n 2 (2) ... Lnm (2)
L1n1 L2 n1 L3n1 L4 n1 L1n 2 L2 n 2 L3n 2
L4 n 2 ... L1nm L2 nm L3nm L4 nm
any positive integer l.
Proof:
Assume that Cr [K m ] decomposes into m
sunlet graph Ln , from theorem (4.4)
2
Ln (l )
decomposes into l sunlet graph
Therefore proper even list of sunlet graphs packs G(2) .Hence the result .
4.4 Theorem
Ln for any positive integer l.
Cr [K ml ]
Ln1 (l ) Ln 2 (l ) ... Lnm (l )
If the graph Cr [K m ]
decomposes into
1 ... L l 2
... L 1
... Ll 2
sunlet graph Ln , n = rm, r,m even,
then the graph Cr [K ml ] decomposes into sunlet graphs Ln for any positive
Which is an even list of Ln .Hence any proper even list of sunlet graph Ln
integer l .
Proof:
From the previous observation Ln
packs G(l )
4.6 Theorem
for any positive integer l .
decompose Cr [K m ] , n = rm, r,m even.
If the graph Cr [K m ]
decomposes into
Next show that Ln [ Kl ] , can be
sunlet graph Ln , n = rm , m even,
ndecompose into l 2 , copies of L .
then the graph Cr [ K ml ]
decomposes into
Label the vert ices of
Ln [K l ] , as
sunlet graph Lnl
Proof:
for any positive integer l.
x a ij ,1 a l ,Then form the sunlet
Suppose Cr [K m ]
decomposes into m
sunlet graphs Ln
which follows from
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International Journal of Scientific & Engineering Research Volume 2, Issue 10, Oct-2011 7
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lemma (3.2)and (3.3).It is sufficient to
4.8 Theorem
show that Ln (l )
can be decompose
The graph Cr [K m ]
can be decompose
into sunlet graph Lnl
where Lnl
is a
into sunlet graph Ln , if and only if n
sunlet graph on nl vertices.Next form
divides rm2 , n rm
and m is even.
sunlet graph Lnl
from Ln (l ) .The cycle in
Proof:
Ln give rise to Cn [Kl ] in Ln (l ) .
2
The necessary condition follows from lemma (3.6) that is the number of edges
2
Cn [Kl ]
can be decompose into l cycles
in Cr [ Km ]
is rm ,so n must divides
2 rm 2
for a decomposition to occur.If
Cnl
2
by lemma (3.2),(3.3).Then join
n > rm,a vertex must be repeated within each sunlet graph which is impossible.
each vertex in each l cycles Cnl
2
to the
If n < rm,then there is a vertex which does
not appear in the sunlet graph which is
pendant vertices xl ij to get l sunlet
also impossible for such decomposition to occur.So n = rm.
graphs
Lnl
i.e
To show that if n | rm2
then Ln
Ln (l ) Lnl1 Lnl 2 Lnll
decomposes Cr [K m ] , it is sufficient to
Hence Lnl
decomposes Cr [K ml ]
for any
show that if r | n
n | rm2 .
and m | n
then
positive integer l.
Case 1: r divides n
4.7 Corollary
Write n rq 2t
where t, q is a positive
Let G Cr [ K m ]
be a graph with sunlet
integer and from lemma (3.6),
graph decomposition,then any proper
rq 2t | rm2 ,so qt | m ,and we can write
even list of sunlet graph Lnl
for any positive integer l .
packs G(l )
m qq't .Also rq 2t rqq't ,so
q q' .Next consider C [K ] , the degree
r t
Proof:
Assume that proper list of sunlet
(L nl1 , L nl1,..., L nl1 , L nl 2 ,
of each vertex is 2t which is even.Each vertex appears t times in the sunlet graph
Lrt
1 2 l 1
graphs
l 1 l
decomposition which follows from
lemma (3.2) and lemma (3.3).By theorem
..., L nl 2 ,..., L nlm ,..., L nlm
´
(4.4),the graph Cr [K
qq 't ]
can be
is the proper list of sunlet graphs Lnl .Let
decompose into sunlet graph
Lrt .Applying theorem (4.6),we have that
Ln1 Ln 2 ... Lnm
decomposition of G.i.e
be a sunlet graph
Cr [K
qq 't ]
decomposes into sunlet graph
L L 2
for q q' .Hence if r
Lnk Ln , k 1,2,..., m . By theorem (4.6),
rqq 't
rq t
1 2 l
Lnk (l ) L nlk L nlk ... L nlk .
L nlk L nlk ... L nlk
divides n then Cr [K m ]
decomposition.
has sunlet graph
1 2 l
Whence
Case 2: m divides n
Write n mt'
for any positive integer
G(l ) Ln1 (l ) Ln 2 (l ) ... Lnm (l )
t ' 3
and m qq'
1 2 l 1
(L nl1 L nl1 ... L nl1 L nl 2
Ther
Case 2a: Suppose m 2(mod 4)
and let
l 1 l
... L nl 2 ... L nlm ... L nlm
q = 2,then q' 1(mod q) .By lemma (3.1)
efore any even list of sunlet graphs Lnl
packs G(l ) .
Ct '[Kqq '
] decomposes into sunlet graph
Lt ' q
and by theorem (4.6), Ct '[Kqq ' ]
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International Journal of Scientific & Engineering Research Volume 2, Issue 10, Oct-2011 8
ISSN 2229-5518
decomposes into sunlet graph
Lt 'qq ' Lt 'm .Hence sunlet graph Ln
decomposes Cr [ Km ] for r t ' .
Case 2b: Suppose m 0(mod 4) .Let q =
[6] D. Froncek, P. Kovar, M. Kubesa, Decomposition of complete graphs into blown-up cycles Cm[2]; Discrete Mathematics 310 (2010),1003-1015.
[7] R. Anitha, R.S. Lekshmi, N-sun
decomposition of complete,complete
2,then
q' 0(mod q) . Ct '[ Kqq' ]
bipartite
and some harary graphs; Int. J. of
decomposes into sunlet graph Lt 'q by
Computational and Mathematical
lemma (3.1),also Ct '[Kqq ' ]
decomposes
sciences 2 Winter (2008).
[8] D. Sotteau; Decomposition of Km;n
into sunlet graph Lt ' qq ' Lt ' m
by theorem
³K¤ m;n into cycles (circuit) of length
(4.6).Hence sunlet graph Ln
decomposes
2k, Journal of Comb. Theory,Series B
Cr [ Km ] for r t ' . Since sunlet graph
Lrqq' , decomposes Cr [Kqq ' ] for both q' = positive odd integer and q' =positive even integer,therefore it is true for all positive
integer q' .Hence if m divides n then
Cr [ Km ] has sunlet graph decomposition. Since q = 2 all through for m qq' ,it follows that for sunlet graph Ln to
decompose Cr [ Km ] ,m must be an even integer which also follows from lemma (3.4) .
[1] B. Alspach, H. Gavlas, Cyle decomposition of Kn and Kn ¡ I,J. Combin. Theory Ser.B,81 (2001), 77-99.
[2] M. Sajna, Cycle decomposition of Kn
and Kn ¡ I ,Ph.D Thesis,Simon
Fraser University 1999.
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A. D. Akinola
Department of Mathematics, College of Natural Science, University of Agriculture, Abeokuta,Ogun State, Nigeria. email:abolaopeyemi@yahoo.co.uk
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